1/2b^2-5/2b-42=0

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Solution for 1/2b^2-5/2b-42=0 equation: 


b in (-oo:+oo)

(1/2)*b^2-((5/2)*b)-42 = 0

(1/2)*b^2+(-5/2)*b-42 = 0

1/2*b^2-5/2*b-42 = 0

DELTA = (-5/2)^2-(-42*1/2*4)

DELTA = 361/4

DELTA > 0

b = ((361/4)^(1/2)+5/2)/(1/2*2) or b = (5/2-(361/4)^(1/2))/(1/2*2)

b = 12 or b = -7

b in { -7, 12 }

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